Wednesday, 25 December 2013

Lesson 3 Data Collection

Tithi Paul

1. Observations
+pGLO LB/amp
+pGLO LB/amp/ara
-pGLO LB/amp

-pGLO LB
2.     How much bacterial growth do you see on each plate, relatively speaking?
There is more bacterial growth on the + (Transformation) plates than the – (control) plates. The + pGLO plates had the most bacterial growth, while –LB/amp had no bacterial growth.
3.      What colour are the bacteria?
The bacteria appears white under normal and UV light except for +LB/amp/ara, which appears white under normal lighting and glows bright, neon green under UV light.

4.      How many bacterial colonies are on each plate (count the spots you see).
There are about 92 bacterial colonies on the +LB/amp/ara plate. There are no bacterial colonies on the –pGLO plates and the colonies in the +LB/amp plate were too small and there were too many of them to count individually.

Tuesday, 24 December 2013

The Procedure

Tithi Paul
  1. Two micro test tubes were obtained, one was labelled +pGLO and the other was labelled –pGLO.
  2. Using sterile transfer pipet, 250 µl of transformation solution (CaCl2) was added to each test tube and the transfer pipet was placed in the beaker of bleach solution.
  3. The tubes were placed on a foam micro centrifuge tube holder, which was then placed on ice.
  4. Using a sterile loop, 2-4 large colonies of bacteria, which are circular with smooth edges, were scraped off the starter plate.
  5. The sterile loop was immersed into the solution in the +pGLO test tube and spun between the thumb and index finger a couple times (until the entire colony was dispersed in the transformation solution).
  6.  Steps 4 and 5 were repeated for –pGLO test tube using a new sterile loop.
  7. Another new sterile loop was immersed into the pGLO plasmid DNA stock tube and a loopful was taken out and mixed into the +pGLO tube.
  8. The tubes were returned to the rack on ice and incubated there for 10 minutes.
  9. The LB nutrient agar plates were labelled as: LB -, LB/amp +, LB/amp –, and +LB/amp/ara and with the group numbers
  10. Both of the test tubes, with the foam rack as a holder, were transferred to a water bath with a temperature of 42C for exactly 50 seconds.
  11. The test tubes were then incubated on ice for another 2 min.
  12. The rack with the test tubes were then placed on the lab bench top and 250 µl of LB nutrient broth was added to each tube with a new sterile pipet.
  13. Using a new sterile pipet for each tube, 100 µl of the transformation and control suspensions were added to the appropriate nutrient agar plates.
  14. Using a new sterile loop, the suspensions were evenly spread around the surface of the LB nutrient agar by crosshatching.
  15. The plates were stacked up (negatives at the bottom and positives on top) and taped together.
  16. The stack of plates were flipped upside down and incubated in the incubator at 37Celsius for two days (over the weekend).

Lesson 4: Extention Activity : Calculate Tranformation Efficiency

By: Jathuya Peranantharuban and Leeza Yackballick

1.                   Determining the total number of green fluorescent cells

The total number of colonies is 107.

2.                   Determining the amount of pGLO plasmid DNA in the bacterial cells spread on the LB/amp/ara plate.
2.
a.                    Determining the total amount of DNA
 (DNA in µg) = (concentration of DNA in µg/µl) x (volume of DNA in µl)
=  0.08 µg/µl x 10 µl
= 0.8 µg
The total amount of pGLO DNA used in this experiment is 0.8 µg.

·                     What will this number tell you?
This piece of information will help us calculate the amount of DNA spread on the agar plate to determine the transformation efficiency.

b.  Determining the fraction of pGLO plasmid DNA (in the bacteria) that actually got spread onto the LB/amp/ara plate

Fraction of DNA used = Volume spread on a LB / amp plate (µl) / Total sample volume in text tube (µl)
                                                        = 100 µl / 510 µl
                                                                        = 0.20
The fraction of pGLO plasmid DNA spread on the LB/amp/ara plate is 0.20.

·                     What will this number tell you?
This piece of information will also  help us calculate the amount of DNA spread on the agar plate to determine the transformation efficiency.

So, how many micrograms of DNA did you spread on the LB/amp/ara plates?

pGLO DNA spread (µg) = Total amount of DNA used (µg) x fraction of DNA
                                            = 0.8 µg x 0.20
                                           = 0.16 µg
There are 0.16 micrograms of pGLO DNA was spread on the LB / amp / ara plates.
Number of colonies on the LB / amp / ara plate =
107
Micrograms of pGLO DNA spread on the plates
0.16 µg

Transformation efficiency = Total number of cells growing on the agar plate / Amount of DNA spread on the agar plate
                                                  = 107 / 0.16 µg
                                                  = 668.75
The transformation efficiency of this experiment is 669 tranformants/ µg.
Analysis

·                     Scientists would report 10,000 tranformants/ µg as 10tranformants/ µg.
·                     Scientists would report 40,000 tranformants/ µg as 4 x 10tranformants/ µg.
·                     Scientists would report 960,000 tranformants/ µg as 9.6 10tranformants/ µg.

·                     Scientists would report 669 tranformants/ µg as 6.69 x 10tranformants/ µg.

·                     Use a sentence or two to explain what your calculation of transformation efficiency means:

This number should indicate how effective we were in getting DNA molecules into bacterial cells. The transformation efficiency represents the total number of bacterial cells that expresses the green protein divided by the amount of DNA used in the experiment.

·                     How does your transformation efficiency compare with the above?

Compared to the values indicated by biotechnologists, our values are generally low.  The transformation protocol has a transformation efficiency of between 8.0 x 10and 7.0 x 103, whereas the number we calculated is 6.69 x 102.

·                     Calculate the transformation efficiency.
Number of colonies on LB/amp/ara plate
227 colonies
Micrograms of DNA spread on the plates
Total amount of pGLO DNA used in the experiment
 =  ( 10 µl ) x ( 0.08 µg/ µl)
                      =  0.8 µg
Fraction of DNA = ( 100 µl) /  ( 250+10+250 µl)
                     = 0.20
pGLO DNA spread = (0.8 µg) x (0.20)
                     = 0.16 µg
Transformation efficiency =
= 227 colonies /  0.16 µg
= 1418.75 tranformants/ µg.
= 1.4 x 10tranformants/ µg.

·                     Extra Credit Challenge

Transformation efficiency =  3 x 10bacteria/ µg
Micrograms of DNA spread on the plates = 0.16 µg
Number of colonies = Transformation efficiency x Micrograms of DNA spread
                                      =  3 x 10bacteria/ µg x 0.16 µg
                                      =  480 colonies
480 transformant colonies would be expected to grow on the LB/amp/ara plate.

Lesson 3 Review Questions

By: Jathuya Peranantharuban and Leeza Yackballick


What’s Glowing?

1.                   Recall what you observed when you shined the UV light source onto a sample of
original pGLO plasmid DNA and describe your observations.

When the UV light was shined on the sample of the original pGLO plasmid DNA,  no fluorescence colour was observed, and did not change in appearance under the UV light.

2.                   Which of the two possible sources of the fluorescence can now be eliminated?

The original bacteria and the pGLO plasmids DNA can be eliminated since no fluorescence colour was observed under the UV light.

3.                   What does this observation indicate about the source of the fluorescence?

This observation indicates that the source of of fluorescence is related to the protein in the DNA of the transformed plasmids. The fluorescence green light was only observed in the DNA of the bacteria that contains the pGLO plasmid DNA, LB nutrient, Ampicillin and Arabinose.  This observation indicates the source of fluorescence is from the gene that codes for green fluorescent protein from the bioluminescent jellyfish Aequorea victoria. This gene allows the transformed bacteria to glow a bright green colour under ultraviolet light.

4.                   Describe the evidence that indicates whether your attempt at performing a genetic transformation was successful or not successful.

The evidence that would indicate whether our attempt at performing a genetic transformation was successful or not depends on the end observations. If the transformed bacteria display the desired characteristic then we have successfully performed genetic transformation. In this case,  if the plate with +pGLO LB/amp/ara and +pGLO LB/amp have colonies of bacteria, and the colonies on the +pGLO LB/amp/ara plate should fluoresce bright green under UV light. If the experiment was unsuccessful then colonies of bacteria will not be present on the  +pGLO LB/amp/ara and +pGLO LB/amp plates.  Errors that may affect the results include not transferring appropriate number of colonies to the plates or mistakes in following the instructions as indicated in the procedure.

The Interaction between Genes and Environment

Some E.coli did grow on the LB plate that does not contain ampicillin  or arabinose.

1.                   From your results, can you tell if these bacteria are ampicillin resistant by looking at them on the LB plate? Explain your answer.

From our results, we cannot tell if these bacteria are ampillicin restistent by looking at them on the LB plate.  We are not able to distinguish the colonies that are ampicillin resistant and those that are ampicillin sensitive since they look similar. The bacteria on the LB plate and the bacteria on the LB/amp plate look alike, so therefore there is not a physical feature to indicate whether they are ampicillin resistant.

2.                   How would you change the bacteria’s environment to best tell if they are ampicillin resistant?

To best tell if they are ampicillin resistant, we can change the bacteria’s environment. To test whether the bacteria are resistant to ampicillin, some bacteria  can be transferred from the LB plate to the LB/amp plate. If the bacteria are able to grow on the LB/amp plate, this would show the bacteria are resistant to ampicillin, whereas if the bacteria do not survive, they are ampicillin sensitive. The plasmids that are able to survive contain the gene resistant to the antibiotic, and therefore when the plasmids are placed in the new environment with the antibiotic, the colonies can continue to grow.

3.                   Very often an organism’s traits are caused by a combination of its genes and the environment it lives in. Think about the green color you saw in the genetically transformed bacteria:

a.  What two factors must be present in the bacteria’s environment for you to see the green color? (Hint: one factor is in the plate and the other factor is in how you look at the bacteria).

The two factors that must be present is the appropriate solutions and environment. The sugar arabinose must be present to activate the GFP gene.  This gene is next to the arabinose promoter, so it becomes active in the presence of arabinose. In addition, UV light is necessary to cause the GFP protein to fluoresce.

b. What do you think each of the two environmental factors you listed above are doing to cause the genetically transformed bacteria turn green?           

When these two factors are present, the transformed bacteria display the gene from the jellyfish.  The original plasmid contained three different genes ,ara A, ara B, and ara D that code for three enzymes needed to convert arabinose to a form that can be used. A fourth gene, araC, codes for a protein that acts to control the structural genes. When arabinose is present, it initiates transcription by promoting the binding of RNA polymerase. The arabinose interacts with araC and causes araC to change its shape. In the transformed plasmids, the promoter (PBAD) and the araC gene are present but the ara A, ara B, and ara D genes are replaced by the GFP gene. Therefore, in the presence of arabinose, araC protein promotes the binding of RNA polymerase and GFP is produced. Furthermore, the long-wave UV light give the gene the energy to fluoresce the green colour.

c.  What advantage would there be for an organism to be able to turn on or off particular genes in response to certain conditions?

Gene regulation is an important feature that allows organisms to survive and prevent producing unnecessary proteins. This allows the organism to produce proteins only when needed and according the their environment. Moreover, control of the gene is important to allow a cell to create the gene products it needs when it needs them. This gives cells the flexibility to adjust to a new environment, external signals, damage to the cell, food, etc. Examples include the Lac operon in E.Coli, a negative control system, that breaks down lactose when present. Another example is a positive control system since E.coli need tryphospho to produce proteins, the Trp operon is usually “on”.



Monday, 23 December 2013

Lesson 2- Review Questions

By: Shadman Siddique

1) On which of the plates would you expect to find bacteria most like the original non-transformed E. coli colonies you initially observed ? Explain predictions

Ans: I would expect the petri dish labelled LB/amp(-) because in this petri dish none of the bacteria have the vector that would cause it to transform. Thus they would remain unchanged.

2) If there are any genetically transformed bacterial cells, on which plate(s) would they
most likely be located? Explain your prediction.

Ans: The transformed bacteria would appear in the LB/amp(+) and LB/amp/ara plates because in these plates the bacteria have the appropriate vector to cause the transformation. The results confirm this.

3) Which plates should be compared to determine if any genetic transformation has
occurred? Why?

Ans: LB/amp(-) and LB/amp(+) because between those two samples on of them has been treated with the vector while the other hasn't. So if there is a change to occur we can predict that the change will occur in the one that is treated. This will provide us with clear observations of the changes.

4) What is meant by control plate? What purpose does a control serve?

Ans: The control plate is a sample that is made to compare the other samples to. In this experiment the control plates were the two negative LB/amp plates. These plates are not treated with the vector thus they will not show any changes. When compared to the transformed plates it will be very easy to see what has changed.

Transformed Sample

Non- transformed sample (control plate)









Thursday, 19 December 2013

Lesson 1: Focus Questions

By: Sobiga Vyravanathan

Consideration 1: Can I Genetically Transform an Organism? Which Organism?

1) To genetically transform an entire organism, you must insert the new gene into every cell in the organism. Which organism is better suited for total genetic transformation- one composed of many cells, or one composed of a single cell?

An organism composed of a single cell would be best suited for total genetic transformation. This is because an organism with one cell only needs to take the new gene into one cell which is more efficient and faster than inserting the gene into every organism.

2) Scientists often want to know if the genetically transformed organism can pass its mew traits on to its offspring and future generations. To get this information, which would be a better candidate for your investigation, an organism in which new generation develops and reproduces quickly, or one which does this more slowly?   

The better candidate would be the organism in which the new generation develops and reproduces quickly. This is because the quicker the organism reproduces, the scientist can see if the trait was actually passed on to the next generation or if modifications need to be made.

3) Safety is another important consideration in choosing an experimental organism. What traits or characteristics should the organism have (or not have) to be sure it will not harm you or the environment?

The organism should not be antibiotic resistant because if it were antibiotic resistant, and the scientist were infected, antibiotics could not be used to treat the disease. Also the organism should not be UV resistant because UV is sometimes used to kill the organism. The organism should not release poisonous, toxic, virulent, and pathogenic substances to the air especially if these things would make you sick or would cause bodily harm to you. When interacting with plants or animals, this organism should not transmit a disease to the plants or animals. You also want an organism that can be contained in a lab environment that will not leave its position.

4) Based on the above considerations, which would be the best choice for a genetic transformation: a bacterium, earthworm, fish, or mouse? Describe your reasoning.

A bacterium would be the best choice for a genetic transformation because bacteria are single celled which makes it best suitable to find results quickly and efficiently. A bacterium can be kept in a lab in small lab equipment and will not contaminate the air. Most bacteria are not virulent.

Bacteria
Retrieved from http://www.newhealthguide.org/images/19999893/image001.jpg


Consideration 2: How Can I Tell If Cells Have Been Genetically Transformed?

1) Describe how you could use two LB/agar plates, some E. coli and some ampicillin to determine how E. Coli cells are affected by ampicillin.

The two LB/agar plates will be have the same amount of E. coli on them. The difference is that one LB plate will have only agar while the other LB plate has both agar and ampicillin. The LB plate with agar and ampicillin will have more colonies than the one with agar only if the ampicillin positively affected the E. coli. The LB plate with agar and ampicillin will have less colonies than the one with agar only if the ampicillin negatively affected the E. coli. If both the plates have the same amount of E. coli, it is clear that ampicillin had a neutral effect on E. coli.    

Structure of Ampicillin
Retrieved from http://www.nawipro.de/images/stories/nawipro/Antibiotika/ampicillin1.jpg


2) What would you expect your experimental results to indicate about the effect of ampicillin on the E. coli cells?

I would expect my experimental results to indicate that the bacteria were killed by ampicillin as that is the function of an antibiotic. I would be shocked to see colonies of bacteria living because that would mean the bacteria is resistant to ampicillin.